Question

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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given :-

The area of a triangle is 2x^2+4x

base = x+2

To find :-

Find its altitude ?

Solution:-

Given that

The base of a triangle = x+2

Let the altitude of a triangle be h

We know that

Area of a triangle = (1/2)bh sq.units

Area of the given trianagle

= (1/2)(x+2) (h) sq.units

According to the given problem

The area of a triangle is 2x^2+4x

=> (1/2)(x+2) (h) = 2x^2+4x

=> (x+2)(h) = 2(2x^2+4x)

=> (x+2)(h) = 4x^2+8x)

=> h = (4x^2+8x)/(x+2)

=>h = 4x(x+2)/(x+2)

=>h = 4x

Therefore, altitude = 4x

Answer :-

The altitude of the given trianagle is 4x

Check :-

Base = (x+2)

Altitude = 4x

Area of a triangle = (1/2)bh sq.units

=> (1/2)(x+2)(4x)

=> (4x)(x+2)/2

=> (2x)(x+2)

=> (2x)(x)+(2x)(2)

=> 2x^2+4x

Verified the given relations in the given problem.

Used formulae:-

Area of a triangle = (1/2)bh sq.units

Where b is the base and h is the height or altitude of the triangle .