Pls give answer of ii and iv
Answers
Answer:
5). in first triangle
25°+40°+ <3rd =180°
65°+<3rd=180°
<3rd=180°-65°
=115°.
<3rd + x= 180°
115°+x=180°
x=180-115
x=65°
in second triangle
x+45+<3rd =180
65+45+<3rd=180
110+ 3rd=180
3rd= 70°
in third triangle
<3rd+70°=180
<3rd=180-70
3rd=110°
y+45°+3rd=180
y+45+110=180
y+155. =180
y=180-155
=25°
Answer:
1)angle A+ angle B+angle C=180
17+35+angle C=180
angle c=180-54
angle c=126°
on straight line BD
angle ACB+angleACD=180 (linear pair)
126+x=180
x=180-126
x=54°
angleAED=angle ACD=angle EDC
Y=54+52
Y=106°
2)on straight line AC
angleAED+angle CED=180 ( LP)
95°+angleCED=180
angle CED=180-95=85
angC+angE +angD=180
85+40+angD=180
angD=180-125
angleEDC=55
ON LINE BC
angle EDB+angle EDC=180 (LP)
angle EDB=180-55=125
angleAED=angle FAE
95=95
angleEAB=180-95=85
angle A+B+D+E=360(quardilateralsum property)
85+x+125+95=360
x=360-305
x=55°
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