Question

Pls give answer of this ​

Answer 1

$\huge\underline\bold{AnsweR}$

Given-

Cuboidal box of sides

20cm , 30cm and 10cm

To find-

Maximum lenth of the rod that can be kept in a cuboidal box.

Solution-

We have to find the diagonal of this cuboidal box. And the formula is

$\sqrt{(l)^{2} + (b)^{2} + ({h})^{2} }$

☞$\sqrt{(20)^{2}+ ({30})^{2} + ({10})^{2} } cm$

☞$\sqrt{400 + 900 + 100} cm$

☞$\sqrt{1400}$

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Some more formule for cuboid-

• Surface area- $\sf{2(lb+bh+hl)}$
• Lateral surface area- $\sf{2(l+b)h}$
• Volume of cuboid- $\sf{l×b×h}$

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