Question

Pls give answer of this question and Don't spam​

Answer 1

$\huge {\mathfrak {\blue {Solution}}}$

$\large {\mathtt {\boxed {\green {1st \:Method}}}}$

(x³ + 3x²y + 3xy² - 2) - (x³ - 2xy² + 5x²y - 6)

= x³ + 3x²y + 3xy² - 2 - x³ + 2xy² - 5x²y + 6

= x³ - x³ + 2xy² + 3xy² - 5x²y + 3x²y + 6 - 2

= 5xy² - 2x²y + 4 (Ans— the terms can be written in any order but with correct signs)

$\large {\mathtt {\boxed {\green {2nd \:Method}}}}$

$\huge{\binom{ \:\:{x}^{3} - 3x {y}^{2} + 3 {x}^{2}y - 2 }{-({x}^{3} - 2x {y}^{2} + 5 {x}^{2}y - 6})}$

5xy² - 2x²y + 4

Here I have tried to show the column method, but forgive me for the placement of the brackets, could not align >.<

Hope this helped you, thanks for posting :)