Question

pls give answer pls ​

Answer 1

Step-by-step explanation:

If 2root3 is the equation x2+px-6=0 then it will satisfy the following equation

${(2 \sqrt{3}) }^{2} + p(2 \sqrt{3} ) - 6 = 0$

$p = \frac{6}{2 \sqrt{3} } = \sqrt{3}$

then

${x}^{2} + \sqrt{3} x + q \: has \: equal \: roots$

if a quadratic equation has zero roots then its discriminant is 0

so 3-4q=0

q=3/4

q= 0.75

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