Question

pls give answer
pls give answer
pls give answer​

Answer 1

$a^{2} + \frac{1}{a^{2}} - 2 - 3a + \frac{3}{a} = 0\\\\ (a-\frac{1}{a} )^{2} -3 (a - \frac{1}{a} ) = 0\\\\ (a - \frac{1}{a} )(a - \frac{1}{a} - 3 ) = 0$

Therefore we can say a = ±1 by taking a - 1/a = 0

By taking a - 1/a - 3 as 0 we get :

$a - \frac{1}{a} = 3\\\\ \frac{a^{2} - 1}{a} = 3\\\\\\a^{2} - 1 = 3a\\\\\\a^{2} - 3a - 1 = 0$

By using Quadratic formula

a = $\frac{3 + 2\sqrt{2} }{2}$ & $\frac{3 - 2\sqrt{2} }{2}$

So the final 4 values of a are ±1 and (3±2√2)/2

Hope this helps (✿◠‿◠)