Math, asked by 2877w, 1 month ago

pls give answer to this

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Answered by Krish1735
1

Complete step-by-step answer:

First, before we solve this problem, we try to understand how we can arrange 5 men and 4 women in a row without any constraints. To count the number of combinations for this case, we basically have 9 people (we have no constraints so there is no difference between men and women while counting the number of combinations), we have the combinations as 9!

However, the required number of cases with constraints, clearly we would have a lesser number of cases than 9! arrangements. Thus, to give an idea about the current problem, we have,

M W M W M W M W M (Basically, our arrangement would look like this since women would occupy even places.)

Thus, the places for the women are fixed, thus the total number of arrangements is 4! (which is 4P4).

Similarly, due to the women’s places getting fixed, men’s places automatically fixed, thus the total number of arrangements is 5! (which is 5P5). Now, combining these results, we have a total number of combinations of 4!×5!=2880.

Answered by Anonymous
2

Answer:

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