Math, asked by dkdarshana03, 11 months ago

pls give correct answer soon ....... I'll mark as brainliest.....​

Attachments:

Answers

Answered by krishiv07
1

Answer:

OPTION C

+ OR - 1

Answered by Anonymous
1

\Large\boxed{Answer}

f(x) = 1 {x²(x - 1)²(x + 1) - x²(x² - 1)(x - 2)} -

x* {2x²(x² - 1) - 3x²(x² - 1)} + (x + 1) *

{2x²(x - 1)(x - 2) - 3x²(x - 1)²}

f(x) = {x²(x² - 1)(x - 1) - x²(x² - 1)(x - 2)} - x*

{-x²(x² - 1)} + (x + 1)*x²(x - 1){2(x - 2) - 3(x - 1)}

f(x) = x²(x² - 1)(x - 1 - x + 2) + x³(x² - 1) +

x²(x² - 1){2x - 4 - 3x + 3}

f(x) = x²(x² - 1) + x³(x² - 1) - x²(x² - 1)(x + 1)

f(x) = x²(x² - 1)(x + 1) - x²(x² - 1)(x + 1)

f(x) = 0

अतः यहां x के किसी भी मान के लिए f(x) का मान शून्य होगा ।

इसलिए ,

f(100) = 0

Similar questions