Math, asked by meenashah3103, 7 months ago

pls give explanation and pls answer fast I'll mark you as branliest if u give correct answer​

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Answers

Answered by grohith0783
1

Answer:

In ΔAPS and ΔBQR

AP = BQ (Given)

PR = QS (Given)

PR + RS = QS + RS (Adding RS to both sides)

PS = QR

∠APS = ∠BQR = 90° (Given)

ΔAPS = ΔBQR (by SAS rule)

Answered by dishu1723
0

Step-by-step explanation:

in tri. (APS) and tri. (BQR)

PR = QS (GIVEN)

ADD RS on both side ...

PR + RS = RS +QS

this implies ,

PS = RQ ---------(1)

NOW,

in (APS) and (BQR)

AP=BQ (GIVEN)

PS = RQ (PROVED ABOVE)

<APS = <BQR (EACH 90)

HENCE (APS) = (BQR) BY (RHS) THEOREM....

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