pls give explanation and pls answer fast I'll mark you as branliest if u give correct answer
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Answer:
In ΔAPS and ΔBQR
AP = BQ (Given)
PR = QS (Given)
PR + RS = QS + RS (Adding RS to both sides)
PS = QR
∠APS = ∠BQR = 90° (Given)
ΔAPS = ΔBQR (by SAS rule)
Answered by
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Step-by-step explanation:
in tri. (APS) and tri. (BQR)
PR = QS (GIVEN)
ADD RS on both side ...
PR + RS = RS +QS
this implies ,
PS = RQ ---------(1)
NOW,
in (APS) and (BQR)
AP=BQ (GIVEN)
PS = RQ (PROVED ABOVE)
<APS = <BQR (EACH 90)
HENCE (APS) = (BQR) BY (RHS) THEOREM....
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