Question

pls give me a answer I'll mark u as brainleist​

Answer 1

Answer:

1

Solution:

$\mathtt{ ({\frac{ {x}^{b} }{ {x}^{c} } )}^{b + c - a} . ({\frac{ {x}^{c} }{ {x}^{a} } )}^{ c + a - b} . ({\frac{ {x}^{a} }{ {x}^{b} } )}^{a + b - c}}$

$\mathtt{using \: identity \: \: \frac{ {x}^{a} }{ {x}^{b} } = {x}^{a - b} }$

$\mathtt{ ({{x}^{b - c} )}^{b + c - a} . ({{{x}^{c - a}) }}^{ c + a - b} . ({{ {x}^{a - b} })}^{a + b - c}}$

$\mathtt{ {{x} }^{(b - c)(b + c - a)} . {{x}}^{(c - a)( c + a - b)} . {x}^{(a - b)({a + b - c})}}$

Now all bases are x hence we can add powers and take single base

$\mathtt{ {{x} }^{(b - c)(b + c - a) + (c - a)( c + a - b) +(a - b)(a + b - c)}}$

Simplifying powers

$\mathtt{ {x}^{ {b}^{2} - {c}^{2} -ba + ac + {c}^{2} - {a}^{2} - cb + ab + {a}^{2} - {b}^{2} - ac + bc } }$

$\mathtt{ {x}^{0} }$

$\mathtt{ {x}^{0} = 1 }$