Question

pls give me all answers pls help I will follow and mark brainly​

Answer 1

Step-by-step explanation:

Given polynomial= ax^2 +6x+2

a= a

b= 6

c= 2

Product of zeros = -1

As we know that ,for a quadratic polynomial

product of zeros = c/a

c/a= -1

2/a= -1

a= 2/-1

2 . sum of zeroes = -3

product of zeroes = 2

Then , the quadratic polynomial=x^2 - ( sum of zeroes )x+ product of zeroes

x^2 -(-3)x +2

x^2 +3x +2

3.Sum of zeroes = -b/a

Here,

a=3

b= -5

c= 1

put the value in the equation

sum of zeroes = -(-5)/3

=5/3

so sum of zeroes is 5/3

4.Let two zeroes be alpha and beta .

a=√2 and b= -√2

we have formula

k(x^2 -Sx p)

where,

k is constant term

s is sum of zeroes

p is product of zeroes

putting the value ,given above

k(x^2 - (√2-√2)x + (√2x-√2)

k (x^2 +0x -2)

k (x^2 -2)

Let's verify

we have equation

x^2 -2=0

x^2 =2

x= √2

Therefore , our equation should be x^2-2.

5.quotient = 3x-5

Remainder = 9x+10

I hope it will help you