Math, asked by rudramkanase, 3 months ago

pls give me answer fast it's urgent​

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Answered by DoctorSensitive
47

 \large {\red {\underline {\overline {\mid {\sf {Solution \: 5:-{\mid }}}}}}}

 Sum \: of \: (a - b) \: and\:  (2a + b) \\ = 3a \\ \\ Subtracting\:  a + 2b\:  from \: the \: sum = 3a - a - 2b \\ 2a - 2b

 \small{\orange {\boxed {\bf {a) 2a - 2b}}}}

 \large {\red {\underline {\overline {\mid {\sf {Solution \: 6:-{\mid }}}}}}}

 Simplifying \\(a + b - 3) - (b - a + 3) + (a - b + 3) \\ = a + b - 3 - b + a - 3 + a - b + 3 \\ = 3a - b - 3

 \small{\orange {\boxed {\bf {c) 3a - b - 3}}}}

 \large {\red {\underline {\overline {\mid {\sf {Solution \: 7:-{\mid }}}}}}}

 y² + y - a = 3 \\ Putting, \: y = 1 \\ 1 + 1 - a = 3 \\ a = -1

 \small{\orange {\boxed {\bf {a) -1}}}}

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