Math, asked by rudramkanase, 2 days ago

pls give me answer fast its urgent​

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Answered by DivineLove
93

 \large{{ \bold{ \underline{Question.1 \:  \:  }}}}

The present Age of Rohit and Mayank are in the Ratio 11:8.8 years later the sum of their ages will be 54 years. what are their present ages ?

 \large{ \bold{ \underline{Given: - }}}

  • Ratio ages of Rohit nad Mayank 11:8

 \large{  \bold{ \underline{To \: Find : - }}}

  • Their present ages .

 \large{ \bold { \underline{Solution : - }}}

  : \implies Let, Rohit's present age = 11 x

 : \implies Mayank's present age = 8x

8 years later,

 :  \implies Rohit's age = 11x + 8

 :  \implies Mayank's age = 8x + 8

 \therefore 11x + 8 + 8x +8 = 54

: \implies19x + 16 = 54

 :  \implies 19x = 38

:  \impliesx = 2

 \:  \:  \:  \:  \:  \:  \:  \:  \: \: \: \:  \:  \: \: \: \large\bold{ \blue{ :\implies}} Rohit's age = 11 × 2 = 22 years

 \:  \:  \:  \:  \:  \:  \:  \:   \: \: \: \:  \: \: \: \: \large{ \bold{ \blue{ :\implies}}} Mayank's age = 8 × 2 = 16 years

  \:  \:  \:  \:  \:  \:  \large{ \boxed{ \mathfrak{ \red{Answer :- \ present \: ages \: are \: 22  \: and \: 16 years.}}}}

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 \large \bold{ \color{black}{ \underline{Question.2 \:  \: }}}

A father's age is 3 times the sum of ages of his two sons. 5 years later he will be twice the sum of ages of his two sons. Find the present age of the father.

 \large{ \bold{ \underline{ \color{black}{Given :  - }}}}

  • Relation of ages between son and father.

 \large{ \bold{ \underline{ \color{black}{To \: Find :  - }}}}

  • Present age of father

 \large{ \bold{ \underline{ \color{black}{Solution :  - }}}}

   \:  \:  \:  \:  \:  \: : \implies let the age of two sons = x

According to the question

 \:  \:  \:  \:  \:  \:  :  \implies Father's age = 3 × x

After 5 years,

 \:  \:  \:  \:  \:  \:  :  \implies two son = x + 5

 \:  \:  \:  \:  \:  \:  :  \implies father's age = 3x +5

According to the question

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \implies \sf(3x + 5) = (x + 5) \times 2 \\   \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  :  \implies  \sf3x + 5 = 2x + 10 \\ \\   \:  \:  \:  \:  \:  \:  : \implies \sf  \: x \:  = 5

Age of father = 3 × 5

 \:  \:    \:  \: \:  \:  \:  \:   \: \: \:  \: \:  \: \: \: \: \:  \:  \:  \:  \:  \:  =  \sf \: 15 \: years

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \large{ \boxed{ \mathfrak{ \pink{Hence, \: the \: age \: of \: father \: is \: 15 \: years.}}}}

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