Question

pls give me answer of this question

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Answer 1

The answer to the question was wrong

Heron's formula:

• $A=\sqrt{s(s-a)(s-b)(s-c)}$,

Where:

• $s=\frac{a+b+c}{2}$.

According to the question:

• $s=3\times\frac{\sqrt{3}}{4}\times \frac{1}{2} =\frac{3\sqrt{3} }{8}$
• The value of s-a, s-b, s-c is equal to $\frac{3\sqrt{3} }{8} -\frac{\sqrt{3} }{4} =\frac{\sqrt{3} }{8}$

Therefore:

→$A=\sqrt{\dfrac{3\sqrt{3} }{2^3} \times(\dfrac{\sqrt{3} }{2^3})^3}$

→$A=\sqrt{(3\sqrt{3} )^2\times \dfrac{1}{2^{12}} }$

→$A=\dfrac{3\sqrt{3}}{2^6}$

→$A=\dfrac{3\sqrt{6} }{64}$

Therefore the answer is incorrect, none of the above.