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Answers
Answer:
1)
2)2cm
Step-by-step explanation:
1)ABCD is a quadrilateral with AC and BD are diagonals intersecting at O.
It is given that diagonals bisect each other.
.. OA = OC and OB = OD
Proving that the quadrilateral is a parallelogram.
In AAOD and ACOB,
OA = OC
ZAOD=<COB...(Vertically opposite angles)
OD = OB
Therefore AAOD=ACOB by SAS Congruence rule.
.. ZOAD = ZOCB
Similarly, we can prove that AAOB = ACOD
... ZABO = ZCDO
So, for lines AB and CD with transversal BD, we can writeZABO and ZCDO are alternate angles and are equal i.e. AB||CD. Similarly, for lines AD and BC, with transversal AC, ZOAD and ZOCB are alternate angles and are equal. Therefore, BC||AD. Thus, in ABCD, both pairs of opposite sides are parallel. Therefore, ABCD is a parallelogram.
Hence, Proved that quadrilateral whose diagonals bisect each other is a parallelogram.
2) If the radius 25 cm so the diameter will be of 25x2=50 cm.If the length of the chord is 48 cm so it is 2 cm away from diameter.Hence,it is 2 cm away from the centre P.
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Answer:
1 Answer = ABCD is a parallelogram
2 Answer = ∴The distance of the chord from the centre of the circle is 7 cm.
Step-by-step explanation:
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