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∠BPD = ∠ACP = 40° [angle in same segment]. Now, in △BPD, we have. ∠PBD + ∠BPD + ∠BDP = 180°. ⇒ ∠PBD + 120° + 40° = 180°. ⇒ ∠PBD = 180° ...
It is given that ∠ACB = 40° and ∠DPB = 120°. Construction: Join the point A and B. ∠ A C B = ∠ A D B = 40 ° (Angle in the same segment). Now in △ B D P we ...
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