Question

pls give me solution as soon as possible ​

Answer 1

Solution

$\dfrac{16\times2^{n+1}\: - \: 4 \times2^{n}}{16\times2^{n+2}\: - \:2\times2^{n+2}}$

$\implies\:\dfrac{16\times 2^{n} \times 2 \: - \: 4\times2^{n}}{16\times2^{n}\times2^{2}\: - \: 2 \times2^{n}\times 2^{2}}$

$\implies\:\dfrac{2^{n}(16\times 2 \: - \: 4)}{2^{n}(16\times2^{2}\: - \: 2\times 2^{2})}$

$\implies\:\dfrac{16\times 2 \: - \: 4}{16\times2^{2}\: - \: 2\times 2^{2}}$

$\implies\:\dfrac{2^{4}\times 2 \: - \: 2^{2}}{2^{4}\times2^{2}\: - \: 2\times 2^{2}}$

$\implies\:\dfrac{2^{2}(2^{3}\: - 1)}{2^{2}(2^{4}\: -\: 2)}$

$\implies\:\dfrac{2^{3}\: - 1}{2^{4}\: -\: 2}$

$\implies\:\dfrac{8\:-\:1}{16\:-\:2}$

$\implies\:\dfrac{7}{14}$

Hence your answer is

$\implies\:\boxed{\dfrac{1}{2}}$

Answer 2

Answer:

1/2

Step-by-step explanation:

solution is here in the attachment.

hope this will help you better .