Question

Pls give me step by step answers

Answer 1

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Answer 2

Angles on a straight line add up to 180

∠AOB + ∠BOC + ∠COD = 180

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∠AOB + ∠BOC + ∠COD = 180

1/2 x + 5( x/2 - 1) + x + 9 = 180

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Find x :

1/2 x + 5( x/2 - 1) + x + 9 = 180

1/2 x + 2 1/2 x - 5 + x + 9 = 180

4x + 4 = 180

4x = 176

x = 44°

.

Angles on a straight line add up to 180

∠AOB + ∠BOC + ∠AOE = 180

.

Find ∠AOE :

1/2 (44) + 5( 44/2 - 1) + ∠AOE = 180

22 + 105 + ∠AOE = 180

∠AOE = 180 - 127

∠AOE = 53°

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Sum of angles in a triangle is 180°

a + b + 53 = 180

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Find a + b:

a + b + 53 = 180

a + b = 180 - 53

a + b = 127°

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Answer: a + b = 127°