pls give me the answer if don't know pls don't answer
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According to the given problem,
Quantity of nitrate = 75%
Quantity of sulphur = 10%
Quantity of charcol = (100 - 75 - 10)%
= (100 - 85)%
= 15%
Amount of charcol = 15% of 20kg of gunpowder
= 15% × 20kg
= (15/100) × 20kg
= (300/100) kg
= 3kg
= 3000g
∴ Amount of charcol in 20kg of gunpowder is 3000g.
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