Math, asked by trishakumari01, 11 months ago

pls give me the answer quickly as possible ​

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Answered by Anonymous
6

Answer:

2.  

First, draw side AB with length of 6cm, and then draw CD with length 4cm, such that angle BAC is 70-degrees and angle ABD is 30-degrees. Since AB and CD are parallel, angles BAC and ACD are supplementary, so angle ACD is 110-degrees. This leaves angle CDB with 360 - (30+70+110) = 150-degrees.

Now form a right triangle with hypotenuse AC by drawing a line perpendicular to AB which intersects CD at point C. This new triangle will have angle measurements of 90-, 70, and 20-degrees. Draw a second right triangle with hypotenuse BD by drawing a line perpendicular to AB and intersecting point D (forming a right triangle with angles of 90-, 30-, and 60-degrees).

If you slide these two right triangles together, the base will measure 2cm (6cm – 4cm) and the opposite angle will measure 80-degrees (20-degrees plus 60-degrees). By the Law of Sines, you will get AC = 1.0154cm and BD = 1.908cm.

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Answered by ItsDynamoGirl
1

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