Question

pls give me the solution of this asap!!!!​

Answer 1

Answer:

Step-by-step explanation:

$\frac{2 + \sqrt{3} }{2 - \sqrt{3} } = a + b \sqrt{3} \\ \frac{2 + \sqrt{3} \times (2 + \sqrt{3}) }{2 - \sqrt{3} \times (2 + \sqrt{3} )} = a + b \sqrt{3} \\ \frac{4 + 4 \sqrt{3} + 3 }{4 - 3} = a + b \sqrt{3} \\ 7 + 4 \sqrt{3} = a + b \sqrt{3}$

so, a = 7 and b = 4