Question

pls give right ans ​

Answer 1

Step-by-step explanation:

tan A = 1/√3

tan 30° = 1/√3

A = 30°

Angle C = 180°-90°-30° = 60°

cosA cosC - sinA sin C

= cos30° cos60° - sin30° sin60°

= √3/2 × 1/2 - 1/2 ×√3/2

=√3/4 - √3/4

=0

Answer 2

Answer:

0

Step-by-step explanation:

Cos A Cos C - Sin A Sin C

Given,

Cos (1/√3) Cos C - Sin (1/√3) Sin C

so,

By considering from right angled

AB = 1

AC = √3

BC =?

so,

by Pythagoras theorem

BC = √{(AC)^2 - (AB)^2

= √{(√3)^2 - 1^2}

= √(3 - 1)

= √2

so we got BC = √2

we know,

Cos theta = x/r {whereas x = Base and

r = Hypotenuse}

Sin theta = y/r {whereas y = perpendicular

and r = Hypotenuse}

Therefore,

Cos A Cos C - Sin A Sin C

= (x/r)×(x/r) - (y/r)×(y/r)

= (1/√3)×(√2/√3) - (√2/√3)×(1/√3)

= (√2/3) - (√2/3)

= (√2 - √2)/3

= 0/3

= 0