pls give right answer with solution .
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the answer you have marked ie. 13 is correct.
the force must be applied such that net torque is zero. torque is equal to force multiplied by distance of point of application of force from the axis of rotation.
therefore
(10×2)+(8×1)-(1×2)-(F×2)=0
20+8-2- 2F=0
26-2F=0
26=2F
F=13 N
plz mark as brainliest if it helped you
the force must be applied such that net torque is zero. torque is equal to force multiplied by distance of point of application of force from the axis of rotation.
therefore
(10×2)+(8×1)-(1×2)-(F×2)=0
20+8-2- 2F=0
26-2F=0
26=2F
F=13 N
plz mark as brainliest if it helped you
Gurbir:
thanks for marking it brainliest
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