Math, asked by zakeehasan6, 2 months ago

pls give roght answer​

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Answers

Answered by bagkakali
0

Answer:

(x^q/x^r)^1/qr×(x^r/x^p)^1/rp×(x^p/x^q)^1/pq

=x^(q-r)/qr.x^(r-p)/rp.x^(p-q)/pq

=x^{q-r)/qr+(r-p)/rp+(p-q)/pq}

=x^{p(q-r)+q(r-p)+r(p-q)}/pqr

=x^(pq-pr+qr-pq+pr-rq)/pqr

=x^0/pqr

=x^0

=1

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