Pls give step by step explanation of this question
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here is your answer
just rationalise the equation given which will help you to get the value but not in root
as tan¤ is given as 4/3 and tan¤ can be written as perpendicular/base
hope it helps
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tan theta = 4/3 = p/b
p = 4, b = 3, h = ?
h = √ p^2 + b^2
h = √ 4^2 + 3^2
h = √ 16 + 9 = √ 25 = 5
√1 - sin theta /1 + sin theta
= √ 1 - p/h / 1 + p/h
= √ 1 - 4/5 / 1 + 4/5
= √ 5 - 4/5 / 5 + 4/5
= √ 1/5 / 9/5
= √ 1/9 =1/3
Hope this will help you...
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