Question

Pls give the answer of the above image clip.
This is very very important question.
It can be a brainliest question.
DAVIAN OF CLASS-7 pls give the answer.
(ch-11 /maths/HOTS /all /p-224)
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Answer 1

Step-by-step explanation:

5 : 12: 13 given

let us take x

perimeter is 60

5x + 12 x + 13 x = 60

30 x = 60

x = 60 / 30 = 2

then 5 × x = 5 × 2 = 10

12 × x = 12 × 2 = 24

13 × x = 13 × 2 = 26

hence Answar is 10 , 24 , 36

3 question

area of square = side × side

area of circle = π r ^ 2

side of square = 14 cm

area of square = 14 × 14 = 196 cm ^ 2

radius of the circle = 7 / 2 = 3.5

area of four circle = 4π r ^ 2

= 4 × 22 / 7 × 35 / 10 × 35/ 10 = 154 cm

hence shaded region = 196 - 154 = 42

2 question

AD = 2× 6 = 12 cm

thus are of semicircle made on base AD

A1 = π r ^ 2 / 2

= 22× 6× 6 / 14 = 56.52 cm ^ 2

given AB = BC = C D

thus we can say that

AB = AD / 3

= 12 / 3 = 4 cm

thus area of semicircle draw on base AB And BD

A 2 = 22× 4 / 14 = 6.28 cm ^ 2

A3 = 22 × 16 / 14 = 25 .12 cm ^ 2

area of shaded region = A1 - A 3 + A4

= 56.52- 25.12 +6.28 = 37.68cm ^ 2

hope u liked it

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Answer 2

$\huge\underline\mathfrak\red{Answer}$

HOTS

Question No—1

Given,

5 : 12 : 13

= 5x + 12x + 13x= 60

30x = 60

x = 2

Now,

5x= 10

12x= 24

13x = 26

Area of Triangle Will be = 1/2×base × height

1/2×10×24

120cm²

Question3:—

Area of square = side × side

Area of circle= πr²

Side of square = 14cm

Area of Square = 14×14= 196cm²

Radius of cirle = 7/2= 3.5cm

Area of 4 circle = 4πr²

= 4 × 22/7 × 35/10 × 35/10

= 154cm²

Hence shaded region = 196—154

42cm

[I only knew the 1st and 3rd Question]

Thanks