Question

pls give the correct answer

Answer 1

Step-by-step explanation:

Here, ABCD is a parallelogram.

∠CBD=40o and ∠BAD=80o.

AD∥BC and BD is a transversal.

∴  ∠ADB=∠CBD            [ Alternate angles ]

∴  ∠ADB=40o.

∴  y=40o.

In △ADB,

⇒  ∠ADB+∠DBA+∠BAD=180o

⇒  40o+x+80o=180o

⇒  120o+x=180o

⇒  x=180o−120o

⇒  x=60o

We get, x=60o and y=40o.

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