Question

pls. give the correct answers and pls. dont give answers like I dont know, this is not there in my syllabus ​

Answer 1

N 1 V 1 = N 2 V 2 , N 1 × 20 = 1/5 × 10

( acid ) ( Na0h )

N 1 = 1/5 × 10/20= 1/10 strength of the acid solution= eg • mass of the acid × normality

= E × 1/10= E /10 g/ l

mass of acid in 100 ml of the solution= 0• 63

( given ) so , E / 100 = 0• 63 or E = 63

mol• mass = basicity × Eq • mass = 2× 63 = 126

sorry