Question

pls give the correct opt fast

Answer 1

Solution:-

For acceleration we use

Acceleration of ( block + wedge ) :-

$: \implies \rm \: a = \dfrac{F}{(M + m)}$

Derive the formula

FBD of block w.r.t ground

with respect to ground block is moving with an acceleration a

$\therefore \: \: \: \: \: \Sigma \: F_y = 0$

$\implies \: N \cos\theta = mg$

and

$\Sigma \: F_x = ma$

$\implies \: N \sin \theta = ma$

For eqs ( i) and ( ii ) , we get

$a = g\tan\theta$

$F = (M + m)a$

$\boxed{F = (M + m)g \tan\theta}$

Now put the value we get force

$F = (16 + 4) \times 10 \times \tan 37 \degree$

$F = 20 \times 10 \times \dfrac{3}{4}$

$F = 5 \times 10 \times 3$

$F = 150N$

Note :- FBD of mass m is attach