pls give this answer .
very urgent.
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In air velocity of light is 3×10
8
m/s and wavelength is 6000A
o
=6000×10
−10
m
We know that c=λ×f , f=frequency
3×10
8
=6000×10
−10
×f
f=5×10
14
Hz
We know that refractive index n=
velocityoflightinmedium
velocityoflightinvacuum
=
v
c
Here c=3×10
8
m/s
So 1.5=
v
3×10
8
⟹v=2×10
8
m/s
Since frequency does not change when light enters from one medium to other.
v=λf
2×10
8
=λ×5×10
14
λ=4×10
−7
m=4000A
o
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