Question

pls give with steps the picture is attached pls find

Answer 1

Answer:

to deal with this type of question first you should know the properties of rhombus.

diagonal of rhombus bisects the angles at vertices( this property is the key point to solve this). ----------(1)

now,

since, <ACD=30°

so, <CEF=30°. (vertically opposite angles)

hence, <ECG=2<ACD

= 60°. (from1)

again,

since, the quadrilateral CEFG is parallelogram. so,

<ECG=<EFG=60°. ----------(2)

and,

since, AD||BC and BC is produced to G and CEFG is a ||gm so,

AD||BG||FE,

<ADC=<CEF=60°. ( angles at vertices of rhombus

is 60°)

and,

<CEF =<CGF==60°. (CEFG is a ||gm)

--------- ( 3)

hence, from (2) and (3)

CEFG is a rhombus

PROVED

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