Question

pls givee me all answers...​

Answer 1

Answer:

dimension is 987654321

Answer 2

Given:

Dimensions of the side of the triangle as $122 m$ , $22 m$ and $120m$ .

Bond amount of 12000 for 1 year.

To find:

1. Dimensions of the advertisement board.
2. Area of the Advertisement board.
3. Cost of painting it at the rate of 1.50 per square meter.
4. Rent to be paid by the buyer.
5. Area of the advertisement board if all the sides are halved.

Solution:

Step 1

The triangular board has sides of dimension 122 m ,22 m and 120 m.

Step 2

For area of the advertisement board,Using Heron's formula, that is

$A=\sqrt{s(s-a)(s-b)(s-c)}$     where  $s=\frac{a+b+c}{2}$  

and a ,b ,c are the sides of the triangle.

Substituting the given information in the given equation, we get

$s=\frac{22+122+120}{2}$

$s=\frac{264}{2} =132$

In Heron's formula,

$A=\sqrt{132(132-22)(132-122)(132-120)}$

$A=\sqrt{132(110)(10)(12)}$

$A=\sqrt{1742400}$

$A=1320m^{2}$

Hence, the area of the triangular advertisement board is 1320 m².

Explanation 3

We have been given the cost of painting as ₹$1.5 /sq. mt$

Hence, the cost of painting $1320sq.mt.$ $=1320$ × $1.5$

                                                                $=$  ₹ $1980$

Therefore, the cost of painting an area of $1320m^{2}$ is 1980 rupees.

Explanation 4

According to the question, the owner has given the advertisement board on a bond amount of ₹ $12000$ for 1 year.

Therefore, the buyer has to pay an amount of ₹ $1000$ per month or ₹$6000$ every 6 months to the owner as rent.

Explanation 5

We have been asked the  area of the triangle, if the sides of the triangle are halved.

Now, the sides of the triangle becomes $11m$ ,$61m$ and $60m$.

Therefore, using Heron's formula, that is

$A=\sqrt{s(s-a)(s-b)(s-c)}$    where $s=\frac{a+b+c}{2}$

and a ,b ,c are the sides of the triangle.

Now, $s=\frac{11+61+60}{2}$

$s=\frac{132}{2}=66$

In Heron's formula,

$A=\sqrt{66(66-11)(66-61)(66-60)}$

$A=\sqrt{66(55)(5)(6)}$

$A=\sqrt{108900}$

$A=330m^{2}$

Final answer:

Hence,

1. The area of the triangular advertisement board is 1320 $m^{2}$.
2. The cost of painting the advertisement board is 1980 rupees.
3. The rent to be paid every month by the buyer is 1000 rupees.
4. If the sides of the triangle are halved, the area of the triangle becomes 330 $m^{2}$.