Question

pls guys answer it guys

Answer 1

When two dies are thrown then the total outcomes becomes 36 which as follows
(1,1),(1,2),(1,3)(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

i)Now doublet means when dies have same number like (1,1),(2,2),(3,3).etc.
Therefore there are 6 doublets therefore
Probability of getting a doublet =6/36=1/6
ii) Now favourable cases of even numbers on both dies are only 9 therefore,
Probability =9/36=1/4
iii) Favourable outcomes of getting a number on either die which is divisible by 3 are 16. Therefore,
Probability = 16/36=4/9
iv) Favourable outcomes of getting a number on either die which is divisible by 2 are 27. Therefore the probability is
probability=27/36=3/4.

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