Question

pls guys answer this question​

Answer 1

Answer:

here,

angle AOC+angle COD+angle DOB=180°

x+90°+y=180°

=> x+y=(180-90)°=90°

again,

angle AOE+angleEOB=180°

=> 3x+72°=180°

=> 3x=(180-72)°=108°

=> x=108/3°=36°

we get,

x+y=90°

36+y=90°

=> y=(90-36)°

=> y=54°

value of y is 54°