Question

pls guys help me asap​

Answer 1

Here's your answer...

Hope it helps you...

Answer 2

Answer:

${64}^{ \frac{ - 1}{3} } ( {64}^{ \frac{1}{3} } - {64}^{ \frac{2}{3} } ) = {4}^{3 \times \frac{ - 1}{3} } ( {4}^{3 \times \frac{1}{3} } - {4}^{3 \times \frac{2}{3} } ) = {4}^{ - 1} (4 - {4}^{2}) = \frac{1}{4} (4 - 16) = \frac{1}{4} \times - 12 = - 3$

The answer is (-3)