Pls guys help
Answers
Step-by-step explanation:
The expression is (\sqrt[4]{256})^{-2}=\frac{1}{16}(
4
256
)
−2
=
16
1
Step-by-step explanation:
Given : Expression (\sqrt[4]{256})^{-2}(
4
256
)
−2
To find : Simplify the expression ?
Solution :
We know that, \sqrt[n]{x}=x^{\frac{1}{n}}
n
x
=x
n
1
Applying in the expression,
(\sqrt[4]{256})^{-2}=(256)^{-\frac{2}{4}}(
4
256
)
−2
=(256)
−
4
2
(\sqrt[4]{256})^{-2}=(256)^{-\frac{1}{2}}(
4
256
)
−2
=(256)
−
2
1
(\sqrt[4]{256})^{-2}=(16^2)^{-\frac{1}{2}}(
4
256
)
−2
=(16
2
)
−
2
1
(\sqrt[4]{256})^{-2}=(16)^{-1}(
4
256
)
−2
=(16)
−1
(\sqrt[4]{256})^{-2}=\frac{1}{16}(
4
256
)
−2
=
16
1
Therefore, the expression is (\sqrt[4]{256})^{-2}=\frac{1}{16}(
4
256
)
−2
=
16
1
#Learn more
Simplify (256)^-(4^-3/2)
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