Math, asked by ramapathi, 1 year ago

pls guys its an urgent make this sum in process

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Answered by nitthesh7
0
From ques,

a+b+c = 0                                          ............(1)

a²+b²+c² = 4                                      .............(2)
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(a+b+c)² = 0²

a²+b²+c²+2(ab+bc+ac) = 0

4+2(ab+bc+ac) = 0

ab+bc+ac = -4/2 = -2                        ..............(3)

Then, From (3)

(ab+bc+ac)² = (-2)²

(a²b²+b²c²+a²c²)+2abc(a+b+c) = 4 

From (1)

(a²b²+b²c²+a²c²)+2abc(0) = 4

a²b²+b²c²+a²c² = 4                             ...............(4)
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From (2)

(a²+b²+c²)² = 4²

(a⁴+b⁴+c⁴)+2(a²b²+b²c²+a²c²) = 16

From (4)

(a⁴+b⁴+c⁴)+2(4) = 16

a⁴+b⁴+c⁴ = 16-8

a⁴+b⁴+c⁴ = 8
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