Question

pls guys question 5 ka answer bta do very important pls guys pls ​

Answer 1

Answer:

a)54    b)140   c)120

Step-by-step explanation:

Answer 2

Answer:

Q5.)=(a.)=Here, The value of required angle is °.84°.

(b.)=Here, The value of required angle is 100°.

(c.)=Here, The value of required angle is 120°.

Step-by-step explanation:

Q5.)=(a)=Here, As per our given question,

As AB is a straight line,

=132°+Angle(cab)=180° (Sum of angles on a straight line is 180°)

=Angle(cab)=180°-132°

=Angle(cab)=48°

Now, As on point B,

=132°+Angle(cba)=180° (Sum of angles on a straight line is 180°)

=Angle(cba)=180°-132°

=Angle(cba)=48°

Now, Value of third angle:

=48°+48°+Angle(acb)=180° (By Angle-sum property of a triangle)

=Angle(acb)=180°-96°

=Angle(acb)=84°.

Hence, The value of Angle(acb) =84°.

(b)As given in this question,

=4x+2x+3x=180° (By Angle-sum property of a triangle)

=9x=180°

=x=180°/9

=x=20°

By putting value of x in the given angles of triangle, we get,

=4×20°=80°

=2×20°=40°

=3×20°=60°

Now, As asked in question,

=Angle(cad)=Angle(cab)+Angle(cba) (Sum of two corresponding interior angles of a triangle is equal to the exterior angle of it)

=Angle(cad)=40°+60°

=Angle(cad)=100°

Hence, The value of Angle(cad) =100°.

(c)=As given in this question,

As given in question that all sides of the triangle are equal, So, its angles will also be equal and is an equilateral triangle,

So, Let the value of angles of this triangle be x,

So,=x+x+x=180° (By angle-sum property of a triangle)

=3x=180°

=x=180°/3

=x=60°

So, The value of all angles of the given triangle is 60°.

Now, As asked value of Angle(acd),

=Angle(acd)=Angle(abc+acb) (Sum of two interior corresponding angles of a triangle is equal to the exterior angle),

=Angle(acd)=60°+60°

=Angle(acd)=120°

Hence, The value of Angle(acd) =120°.

Thank you.