Question

Pls guys solve F.
Its important

Answer 1

Answer:

X=39

Step-by-step explanation:

applying 4times on bs

$\sqrt[4]{2x + 3} = 3 \\ applying \: 4 \: times \: on \: bs \\ 2x + 3 = {3}^{4} \\ 2x + 3 = 81 \\ 2x = 81 - 3 \\ 2x = 78 \\ x = 78 \div 2 \\ x = 39$

Answer 2

$\rm{\sqrt{3 x+13}=5}$

• Square Both Sides

$\to\rm{3 x+13=5^{2}}$

$\to\rm{3 x+13=25}$

• Subtract 13 from both sides

$\to\rm{3 x+13-13=25-13}$

$\to\rm{3 x=12}$

• Divide both sides by 3

$\to\rm{\dfrac{3 x}{3}=\dfrac{12}{3}}$

$\to\rm{x=4}$

________________________

$\rm{\sqrt[4]{2x+3}=3}$

• Take both sides of the equation to the power of 4

$\to\rm{\left(\sqrt[4]{2x+3}\right)^4=3^4}$

$\to\rm{2x+3=81}$

• Subtract 3 from both sides

$\to\rm{2x+3-3=81-3}$

$\to\rm{2x=78}$

• Divide both sides by 2

$\to\rm{\dfrac{2x}{2}=\dfrac{78}{2}}$

$\to\rm{x=39}$