Math, asked by akshatgautam444, 6 months ago

pls guys solve this as fast as possible​

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Answered by amitsnh
2

Answer:

LHS = tan^2A + cot^2A + 2

= sec^2A - 1 + cosec^2A - 1 + 2

= 1/cos^2A + 1/sin^2A -2 + 2

= ( sin^2A + cos^2A) / sin^2Acos^2A

= 1/(sin^2Acos2A)

= cosec^2A.sec^2A = RHS

Answered by imakshatsgupta
0

Hi

Sahana meri pehchan he

Akshat meri jaan he

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