Question

pls guyz help me pls​

Answer 1

Step-by-step explanation:

6)

Given that

AOB is a line

< AOC = 4x-5°

< BOC = x+10°

From the figure,

< AOC and <BOC are linear pair

They are supplementary.

=> AOC + <BOC = 180°

=> 4x-5° + x+10° = 180°

=> (4x+x) +(-5°+10°) = 180°

=> 5x+5° = 180°

=> 5x = 180°-5°

=> 5x = 175°

=> x = 175°/5

=> x = 35°

i) The value of x = 35°

ii) < AOC = 4x-5°

=> 4(35°)-5°

=> 140°-5°

=> 135°

iii) <BOC = x+10°

=> 35°+10°

=> 45°

7) Given that

The angle = 65°

We know that

The complementary angle of x° is 90°-x°

The complementary angle of 65°

=> 90°-65°

=> 25°

Answer :-

6)

I) The value of x° = 35°

ii) < AOC = 135°

iii) <BOC = 45°

7)

The complement of 65° is 25°

Used formulae:-

→ The sum of two adjacent angles is 180° then they are called Linear pair.

→ The sum it two angles is 90° ,they are called Complementary angles.