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2 to the power of 2+log3base2=?
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How do I solve 2 to the power (2+log 3 to the base 2)?
If I’m not wrong it is something like this
2^(2 + log 3 to the base 2)
So OK let’s start.
2^(2+log 3 to the base 2)
we can write it as
2^(log4 to the base 2 + log 3 to the base2)——————-{log 4 to the base 2 = 2}
=2^(log(4 *3) to the base 2)
=2^(log 12 to the base 2)
=12^(log 2 to the base 2)
=12^1
=12
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