Question

pls help......................

Answer 1

In ∆ABC,

$s = \frac{26 + 28 + 30}{2} = \frac{84}{2} = 42cm$

So, Area of ∆ABC

$= \sqrt{42(42 - 26)(42 - 28)(42 - 30)}$

$= \sqrt{42 \times 16 \times 14 \times 12}$

$= 336 \: {cm}^{2}$

Since diagonal divides parallelogram into two congruent triangles,

therefore,

Area of parallelogram = 2 × 336 = 672 cm²

Answer 2

now multiply 336 by 2

you will get the area of parallelogram

a = 26cm, b = 30cm and c = 28cm

p = 26 +28+30

p = 84

s=p/2

s=84/2

s=42