Question

Pls help.

A iron sphere of mass 1 kg moving with a velocity of 20m/s on a cemented floor. It came to rest after travelling at a distance of 50 m. Find the force of friction

Answer 1

force = mass × acceleration
v2=u2+2as
0=400+2×a×50
-400/100=a
-4 =a
force=1×-4
force=-4N

Answer 2

☺ Hello mate__ ❤

◾◾here is your answer...

u = 20 m/s

v = 0 m/s

s = 50 m

According to the third equation of motion:

v^2 = u^2 + 2as

(0)^2 = (20)^2 + 2 × a × 50

a = – 4 m/s2

★The negative sign indicates that acceleration is acting against the motion of the stone.

m = 1 kg

From Newton's second law of motion:

F = Mass x Acceleration

F= ma

F= 1 × (– 4) = – 4 N

Hence, the force of friction between the stone and the ice is – 4 N.

I hope, this will help you.

Thank you______❤

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