Math, asked by vasanthsandesh18, 18 days ago

Pls help all
maths problem in attachment

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Answered by Athul4152
16

\huge\mathfrak\red{question}

Krishna thinks of a number and subtracts 2/9 from it and multiplies by 9 he got 7 times the original number. find the original number.

\huge\mathfrak\blue{Soultion}

let the number be x

given,

(x -  \frac{2}{9} ) \times 9 = 7x \\

 \frac{9x - 2}{9}  = \frac{7x}{9}  \\

 \frac{9x}{9}  -  \frac{2}{9}  =  \frac{7x}{9}  \\

 \frac{9x}{9}  -  \frac{7x}{9}  =  \frac{2}{9}  \\

 \frac{2x}{9}  =  \frac{2}{9}  \\

x = 1 \\

Answered by Reyna17
0

Answer:

The answer is 1

Step-by-step explanation:

Let the number Krishna thought of be the variable x

when we subtract 2/9

we get x-2/9

multiplying by 9

we get 9 (x-2/9)

the result would be seven times the initial number that is 7x

so the final equation would be

9 (x-2/9) =7x

9x - 2 = 7x

9x - 7x = 2

2x = 2

x = 1

you can also verify the answer

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