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Step-by-step explanation:
∆ BAC similar to triangle ∆QRP by SAS
angle A= Angle R
2x + 15 ° = 5x - 60
2x-5x = -60 - 15
-3x = -75
x= 25
Now ,
AB = QR
3x + 10 = 5y + 15
putting the value of x
3 × ( 25) +10 = 5y + 15
85 = 5y + 15
85 - 15 = 5y
70 = 5y
y = 14
thus
x= 25 and y = 14
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