Math, asked by OjasT, 10 months ago

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Answered by amitkumar44481
6

Question :

The length of a rectangle is twice its breadth. If its length is decrease by 9 cm and breadth is increase by 9 l, the area of the rectangle is increase by 81 sq. cm. Find the length of the rectangle.

To Find :

Find the length of the rectangle.

Solution :

Let Length of rectangle be L.

Breadth of rectangle be B.

And area of rectangle be LB.

\rule{90}1

A/Q,

Case 1.

The length of a rectangle is twice its breadth.

  • L = 2B. ___( 1 )

\rule{90}1

Case 2.

If its length is decrease by 9 cm and breadth is increase by 9 l, the area of the rectangle is increase by 81 sq. cm.

  • ( L - 9 )( B + 9 ) = LB + 81.

\rule{90}1

Taking Case 2,

 \tt \longmapsto (L- 9)(B + 9) = LB + 81.

 \tt \longmapsto LB + 9L - 9B - 81= LB + 81.

 \tt \longmapsto 9(L - B) = 81+ 81.

 \tt \longmapsto 9(L - B)= 162.

 \tt\longmapsto L - B= 18. \:  \:  \:  \:  \:  - (2)

Putting the value of L in Equation 2, We get.

 \tt\longmapsto L - B= 18.

 \tt\longmapsto 2B - B = 18.

 \tt\longmapsto B  = 18.

Now, Putting the value of Breadth ( B ) in Equation ( 1 )

 \tt \longmapsto L= 2B.

 \tt \longmapsto L = 2 \times 18.

 \tt \longmapsto L= 36 \: cm.

Therefore, the Length of rectangle is 36 Cm and breadth is 18 Cm.

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