Question

pls help asap need urgently​

Answer 1

Step-by-step explanation:

We have,

$x = \frac{1}{3 - \sqrt{8} } \: \: and \: \: y = \frac{1}{3 + \sqrt{8} }$

Now,

$= > x + y = \frac{1}{3 - \sqrt{8} } + \frac{1}{3 + \sqrt{8} }$

$= > x + y = \frac{3 + \sqrt{8} + 3 - \sqrt{8} }{(3 - \sqrt{8})(3 + \sqrt{8}) }$

$= > x + y = \frac{6}{9 - 8}$

$= > x + y = 6 \: = > {(x + y)}^{2} = 36$