Question

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Answer 1

Answer:

sum of zeroes$= > \alpha + \beta = \frac{ - b}{a } \\ = > \alpha + \beta = - 3 \\ \: product \: of \: zroes \\ = > \alpha \beta = \frac{c}{a} = 2 \\ required \: polynomial \: = {x}^{2} - ( \alpha + \beta ) x + ( \alpha \beta ) \\ = {x}^{2} - ( - 3) x+ (2) \\ = {x}^{2} + 3x + 2$

Answer 2

Answer:

Given :sum of zeros=(-3)

product of zeros=2

Step-by-step explanation:

p(x) = x^2- (sum of zeros) x + product of zeros

putting values

p(x) = x^2-(-3)x + 2

p(x) = x^2 + 3 x +2

Quadratic polynomial with of of zeros (-3) and product of zeros 2 is ----. x^2+3x+2.

Hope it helped