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Concept:-Total work done=change in kinetic energy+change in potential energy
here potential energy is 0
so here
total work done=change in kinetic energy
Area under the f-s graph gives total work done
Solution:-Kinetic energy attained by particle at
L/2=total work done on particle upto distance
L/2=1/2 ×Fmax ×L/2=LFmax/4
kinetic energy at L=1/2 ×Fmax ×L=LFmax/2
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